Class 7 Mathematics Exercise 13.2 Solution in Assamese And English , SCERT Assam Class 7 Maths Exercise 13.2 Chapter QR code N3K6E7 and Chapter QR code R311Q4 Exponents And Powers (সূচক আৰু ঘাত)

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 Exercise 13.2

1. Simplify using laws of exponents (Write the answer in the exponential form):
   (i) 3^5 x 3^7 x 3^10
   (ii) (2^7 x 2^6) ÷ 2^5
   (iii) (2^0 x 2^5 x 2^8) ÷ (2^0 x 2^6 x 2^7)
   (iv) (3^4)^2 x (3^2)^3
   (v) (16^2 x 8^3) ÷ (2^5)^2
   (vi) 3^7 x 5^8 / 21 x 15
   (vii) 25 x 5^0 x 9^4 / 10 x 9^3
   (viii) (2^5)^3 x 16 x 3^0 / (2^3)^5 x 5^0
   (ix) 2^3 x 3^3 / 6^2
   (x) 5^3 x 7^3 x 2^3 / 70^2
   (xi) 7^5 x 3^2 x 6^4 x 4 / (21)^2 x 343 x 2^6 x 81

2. Express in terms of prime factors and write in exponential form:
   (i) 768
   (ii) 729
   (iii) 128 x 625
   (iv) 64 x 729
   (v) 1000

3. Simplify:
   (i) (2a^2b^3)^3 x (3ab^2)^4 / 6^2 x (ab)^5
   (ii) (a^m b^n)^p x (a^p b^m)^n / (ab)^p
   (iii) (ab^2)^3 x (a^2b^3)^4 x (a^3c^2)^3 / (a^2b^2c^2)^2

4. If 3^m = 81, then find the value of m.

5. Check whether true or false:
   (i) 3a^0 = (3a)^0
   (ii) 2^3 > 3^2
   (iii) (5^0)^4 = (5^4)^0
   (iv) 2^3 x 3^3 = 6^5
   (v) 2^5 / 3^5 = (2/3)^(5-5)
   (vi) 2^5 = 5^2

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