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Exercise 13.2
(i) 3^5 x 3^7 x 3^10
(ii) (2^7 x 2^6) ÷ 2^5
(iii) (2^0 x 2^5 x 2^8) ÷ (2^0 x 2^6 x 2^7)
(iv) (3^4)^2 x (3^2)^3
(v) (16^2 x 8^3) ÷ (2^5)^2
(vi) 3^7 x 5^8 / 21 x 15
(vii) 25 x 5^0 x 9^4 / 10 x 9^3
(viii) (2^5)^3 x 16 x 3^0 / (2^3)^5 x 5^0
(ix) 2^3 x 3^3 / 6^2
(x) 5^3 x 7^3 x 2^3 / 70^2
(xi) 7^5 x 3^2 x 6^4 x 4 / (21)^2 x 343 x 2^6 x 81
2. Express in terms of prime factors and write in exponential form:
(i) 768
(ii) 729
(iii) 128 x 625
(iv) 64 x 729
(v) 1000
(i) 768
(ii) 729
(iii) 128 x 625
(iv) 64 x 729
(v) 1000
3. Simplify:
(i) (2a^2b^3)^3 x (3ab^2)^4 / 6^2 x (ab)^5
(ii) (a^m b^n)^p x (a^p b^m)^n / (ab)^p
(iii) (ab^2)^3 x (a^2b^3)^4 x (a^3c^2)^3 / (a^2b^2c^2)^2
(i) (2a^2b^3)^3 x (3ab^2)^4 / 6^2 x (ab)^5
(ii) (a^m b^n)^p x (a^p b^m)^n / (ab)^p
(iii) (ab^2)^3 x (a^2b^3)^4 x (a^3c^2)^3 / (a^2b^2c^2)^2
4. If 3^m = 81, then find the value of m.
5. Check whether true or false:
(i) 3a^0 = (3a)^0
(ii) 2^3 > 3^2
(iii) (5^0)^4 = (5^4)^0
(iv) 2^3 x 3^3 = 6^5
(v) 2^5 / 3^5 = (2/3)^(5-5)
(vi) 2^5 = 5^2
(i) 3a^0 = (3a)^0
(ii) 2^3 > 3^2
(iii) (5^0)^4 = (5^4)^0
(iv) 2^3 x 3^3 = 6^5
(v) 2^5 / 3^5 = (2/3)^(5-5)
(vi) 2^5 = 5^2
Thank You